how do i get the slope formula of: (4,-1) and (3,-1)?
Then the Point slope form:Slope=4,passes through (1,3)?
the line with slope m passing through (h,k) is
y-k = m(x-h)
so, for the 2nd line, you have
y-3 = 4(x-1)
for the first one, find the slope and then you can apply this method.
To find the slope between two points, you can use the slope formula:
slope = (y2 - y1) / (x2 - x1)
For the given points (4, -1) and (3, -1), we can substitute the coordinates into the formula:
slope = (-1 - (-1)) / (3 - 4)
= 0 / -1
= 0
So, the slope between these two points is 0.
Now, let's move on to the second part of your question. To find the equation of a line in point-slope form, we need to know the slope (which is given as 4) and a point that the line passes through (1, 3).
The point-slope form of a linear equation is:
y - y1 = m(x - x1)
Where (x1, y1) is the given point and m is the slope.
Substituting the values into the equation, we have:
y - 3 = 4(x - 1)
Simplifying further, we distribute 4 to both terms inside the parentheses:
y - 3 = 4x - 4
To isolate y, we can add 3 to both sides:
y = 4x - 1
So, the equation of the line with a slope of 4 and passing through the point (1, 3) is y = 4x - 1 in point-slope form.