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need to find: lim as x > 0 of 4(e^2x  1) / (e^x 1) Try splitting the limit for the numerator and denominator lim lim x>0 4(e^2x1) (4)x>0 (e^2x1) ______________ = ________________ lim lim x>0 e^X1 x>0 e^x1 … 
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i need some serious help with limits in precalc. here are a few questions that i really do not understand. 1. Evaluate: lim (3x^32x^2+5) x> 1 2. Evaluate: lim [ln(4x+1) x>2 3. Evaluate: lim[cos(pi x/3)] x>2 4. Evaluate: … 
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Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? 
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Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? 
College Pre Calc
lim t>7 F(x) (1/t)−(1/7)/t7 
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5) Use the L’Hopital’s method to evaluate the following limits. In each case, indicate what type of limit it is ( 0/0, ∞/∞, or 0∙∞) lim x→2 sin(x^2−4)/(x−2) = lim x→+∞ ln(x−3)/(x−5) … 
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lim x → ∞ tan−1(x7 − x9) 
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Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→0 (e^9x−1−9x)/(x^2) 
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Note that f is continuous on (−∞, 6) and (6, ∞). For the function to be continuous on (−∞, ∞), we need to ensure that as x approaches 6, the left and right limits match. First we find the left limit. … 
pre calc help please!!!!
given that lim f(x) = 5 x>x and lim g(x) = 7 x > c find lim [f(x)+g(x)]^2 x> c a. limit does not exist b. 175 c. 4 d. 245 e. 70