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In an old house, the heating system uses radiators, which are hollow metal devices through which hot water or steam circulates. In one room the radiator has a dark color (emissitivity = 0.804). It has a temperature of 65.9 oC. The new owner of the house paints the radiator a lighter color (emissitivity = 0.439). Assuming that it emits the same radiant power as it did before being painted, what is the temperature (in degrees Celsius) of the newly painted radiator?

  • Physics -

    (emissivity)*sigma*T^4 = constant
    sigma is the Stefan-Bolzmann constant, which cancels out.
    T must be in Kelvin

    (0.804)*sigma*339.1^4 = (0.439)*sigma*T^4

    (T/339.1)^4 = 1.8314
    T/339.1 = 1.163
    T = 394.5 K = 121 C

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