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posted by Daisy Tuesday, December 4, 2012 at 5:11pm.
Find all real solution of the equation sin^2x = -2+2cosx
since sin^2 = 1-cos^2, 1-cos^2 = -2 + 2cos cos^2 + 2cos - 3 = 0 (cos+3)(cos-1) = 0 cos=1, so x = 0,2pi,4pi,... why not -3?
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