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Peter has 1200 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed area?

  • Math -

    It's a square.

  • Math -

    So what exactly would the answer be? im confused..

  • Math -

    1200/4 = 300 yards on each side.

    A = 300 * 300

    A = ?

  • Math -

    Oh i see now! Ok thank you!

  • Math -

    Finding the Absolute Area....

    Area of the fence:
    A=x*y

    Perimeter of the fence
    2x+2y=1200

    Then, you solve for one variable
    2x=1200-2y
    x=600-y <-- plug this back into the Area function and you will get

    A=(600-y)y
    A=600y-y^2

    And I believe you can set that equal to zero
    -y^2+600y=0

    Then you use the quadratic formula
    b=600
    a=-1
    so y= -600/(2)*(-1)
    y=300

    That'll give you one side, then plug it back to perimeter equation to get x. Hope this is right!

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    You're welcome.

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