advanced math
posted by kristina .
find the real solutions.
3+ the square root of (2x+2)=x

3+√(2x+2) = x
√(2x+2) = x3
2x+2 = (x3)^2
2x+2 = x^26x+9
x^28x+7 = 0
(x1)(x7) = 0
x = 1 or 7
check for extraneous roots:
3+√(2+2) = 3+2 = 5 nope
3+√16 = 3+4 = 7 ok
so, x=7 is the only solution
x=1 is the solution using the √
3√4 = 1