what is the nickel ion concentration in a solution prepared by mixing 337ml of 0.430M nickel nitrate with 387ml of 0.251M sodium hydroxide?

45

To find the nickel ion concentration in the solution, we can use the concept of stoichiometry and the principles of dilution.

The first step is to determine the moles of nickel nitrate and sodium hydroxide used in the solution. We can do this by using the formula:

moles = concentration (in M) * volume (in L)

For nickel nitrate:
moles of nickel nitrate = 0.430 M * (337 mL / 1000) L

For sodium hydroxide:
moles of sodium hydroxide = 0.251 M * (387 mL / 1000) L

Now, let's determine how these two react based on the balanced equation:

Ni(NO3)2 + 2NaOH -> Ni(OH)2 + 2NaNO3

According to the stoichiometry, 1 mole of nickel nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of nickel hydroxide. Therefore, the moles of nickel hydroxide formed are equal to half of the moles of nickel nitrate used.

moles of nickel hydroxide = (moles of nickel nitrate) / 2

Now, we have the moles of nickel hydroxide. To find the concentration of the nickel ions, we need to determine the total volume of the solution.

Total volume = volume of nickel nitrate solution + volume of sodium hydroxide solution
Total volume = (337 mL / 1000 L) + (387 mL / 1000 L)

Finally, we can calculate the nickel ion concentration:

nickel ion concentration = (moles of nickel hydroxide) / (total volume in L)

By following these steps, you can calculate the concentration of nickel ions in the solution.