math
posted by azmeena .
find the horizontal asymptote of f(x)= 8x/2x^2+1

math 
Steve
as x gets huge, all but the highest powers don't matter, so you have
f(x) > 8x/2x^2 = 4/x > 0
whenever the denominator is a higher power than the numerator, the asymptote is y=0.
Respond to this Question
Similar Questions

Math  horizontal asymptote of f(x) (check)
What is the horizontal asymptote of f(x)=x/(x1)^2 It is supposed to be y=0 but then I even know that b/d is the horizontal asymptote, in this since there is no b, it would be 0/1 which is 0 is the above reasoning correct? 
Precalculus
Write an equation for rational function with given properties. a) a hole at x = 1 b) a vertical asymptote anywhere and a horizontal asymptote along the xaxis c) a hole at x = 2 and a vertical asymptote at x = 1 d) a vertical asymptote … 
college algebra
Given the following rational function, find a. the horizontal asymptote(s), b. the vertical asymptote(s), if any, and c. the oblique asymptote(s), if any. f(x)=(x^2x2)/(2x^2x10) 
College Algebra
Given the following rational functions,find:a.)the horizontal asymptote(s), b.)the vertical asymptote(s), if any,and c.) the oblique asymptote(),if any. f(x)=x(x17)^2/(x+12)^3 
Math
P(x) = (2x^3+x^218x9)/(x^2x6) 1.Find any holes in the graph of P(x) 2.Find any horizontal or oblique asymptote 3.Determine where it crosses the horizontal/oblique asymptote (if it does) 
math
Suppose the the limit as x approaches 6 to the left equals infinity. What conclusion can be made about the graph of y = f (x)? 
PreCalculus
State the Vertical Asymptote, Horizontal Asymptote, domain, range, x intercept and y intercept for the following Function. y= (5x)/(x+3) I already know that the Vertical asymptote is 3, so that means the domain is everything except … 
calculus
The following rational function describes concentration in blood of a certain medicine taken once depending on time, find: A.the horizontal asymptote(s) B.the vertical asymptote(s) C. describe their possible meanings Horizontal asymptote … 
math
Explain why the graph of g(x) = 1/x has a horizontal asymptote. What is the equation of this asymptote? 
Math (Integrals)
The area A between the graph of the function: g(t) = 4  (4/t^2) and the taxis over the interval [1, x] is: A(x) = ∫[1, x] (4  (4/t^2)) dt a) Find the horizontal asymptote of the graph g. I believe the horizontal asymptote of graph …