I got u-(8u^(3/2) over 3) Can anyone check this for me?
2u du = dx x = u^2+4 ∫x√(x-4) dx = ∫(u^2+4)u 2u du = ∫2u^4 + 8u^2 du = 2/5 u^5 + 8/3 u^3 = u^3 (2/5 u^2 + 8/3) = (x-4)^(3/2) (2/5 (x-4) + 8/3) = 2/15 (x-4)^(3/2) (3x+8)
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