When 50.0 Ml of 1.00 m chi was mixed with 50.0 ml of 1.00 m NaOH in a calorimeter the temperature rose from 25.0 c to 32.0 c calculate the heat change for the reaction assuming that the total volume of the solution is 100.0 ml and the specific heat is 1.00 cal/ (g.c). Is the reaction exothermic or endothermic?
Is it m or M? It makes a difference. m is molality; M is molarity.
What is chi?
One down. What's chi?
Hci
To calculate the heat change for the reaction, we can use the formula:
Heat change (q) = mass × specific heat × change in temperature
First, we need to determine the mass of the solution. Since we have 50.0 mL of each solution (CHI and NaOH) and the total volume of the solution is 100.0 mL, the mass can be calculated using the density formula:
Mass = volume × density
Assuming the density of the solution is 1 g/mL (which is close to the density of water), the mass would be:
Mass = 100.0 mL × 1 g/mL = 100.0 g
Next, we need to calculate the change in temperature. The initial temperature is 25.0°C, and the final temperature is 32.0°C, so the change in temperature is:
Change in temperature = Final temperature - Initial temperature
Change in temperature = 32.0°C - 25.0°C
Change in temperature = 7.0°C
Now that we have the mass (100.0 g), the specific heat (1.00 cal/(g °C)), and the change in temperature (7.0°C), we can calculate the heat change using the formula:
Heat change (q) = mass × specific heat × change in temperature
q = 100.0 g × 1.00 cal/(g °C) × 7.0°C
q = 700 cal
Therefore, the heat change for the reaction is 700 calories.
To determine if the reaction is exothermic or endothermic, we can look at the sign of the heat change. If the heat change (q) is negative, the reaction is exothermic, meaning it releases heat. If the heat change (q) is positive, the reaction is endothermic, meaning it absorbs heat.
In this case, since the heat change (q) is positive (700 cal), the reaction is endothermic.