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A 2.24 kg mass on a frictionless horizontal track is attached to the end of a horizontal spring whose force constant is 4.45 N/m. The mass is displaced 3.06 m to the right from its equilibrium position and then released, which initiates simple harmonic motion. How many times does the mass oscillate in 24.2 s?

  • physics -

    First, find the equations that are pertinent to the problem.

    F(spring) = -k*x
    where F(spring) is the force on a spring, k is the spring constant, and x is the displacement.

    w = (k/m)^1/2
    where w is the angular acceleration, m is the mass of the spring

    T = 2*PI/w
    where T is the period of oscillation

    w = (4.45/2.24)^0.5

    T = 2*PI/w

    The number of times the mass will oscillate in 24.2 s is 24.2/T

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