precalculus
posted by amaa .
Solve the given equation. (Enter your answers as a commaseparated list. Let k be any integer.
tan θ = − sqrt 3/3

tanØ = √3/3
from the 306090 triangle, you should recognize that tan 30° = 1/√3 = √3/3
or , using your calculator find tan^1 (√3/3) to get 30°
but the tangent is negative in II and Iv
so Ø = 150°
or Ø = 330°
check with your calculator, it is correct