Calculus [rotation of region bounded by curves]
posted by Ali .
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y=3x^2, x=1, y=0 about the xaxis

volume = π∫(3x^2)^2 dx from x  0 to x=1
= π∫9x^4 dx from 0 to 1
= π [ (9/5)x^5 ] from 0 to 1
= π(9/5  0)
= 9π/5
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