# Calc 1

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integrate from 0 to pi/2 (3sinxcosx)/(1+3sin^2x)^1/2

• Calc 1 -

note that if
u = 1+3sin^2x
du = 6sinxcosx

so you have

∫[1,4] u^(-1/2) 1/2 du
= √u [1,4]
= 1

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