Post a New Question

PHYSICS - PLEASE HELP

posted by .

Part A:
A cardinal (Richmondena cardinalis) of mass 4.50×10^−2 kg and a baseball of mass 0.142 kg have the same kinetic energy. What is the ratio of the cardinal's magnitude p(c) of momentum to the magnitude p(b) of the baseball's momentum?

Part B:
A man weighing 650 N and a woman weighing 460 N have the same momentum. What is the ratio of the man's kinetic energy K(m) to that of the woman K(w)?

  • PHYSICS - PLEASE HELP -

    (A)
    KE₁=m₁v₁²/2= (m₁v₁)²/2 m₁=p₁²/2m₁
    KE₂=m₂v₂²/2= (m₂v₂)²/2 m₂= p₂²/2m₂
    KE₁=KE₂
    p₁²/2m₁=p₂²/2m₂
    p₁²/p₂²=m₁/m₂
    p₁/p₂=sqrt(m₁/m₂)
    (B)
    KE₁= p₁²/2m₁
    KE₂= p₂²/2m₂
    KE₁/KE₂=m₂/m₁

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question