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Algebra2

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25. f(x)= x^2-1 ; -3, -2, -1, 0, 1, 2 ,3
=
f(x); -3^2-1=-10
f(x) ; -2^2-1=-5
f(x) ; -1^2-1=-2
f(x) ; 0^2-1=-1
f(x) ; 1^2-1=0
f(x) ; 2^2-1=3
f(x) ; 3^2-1=8

26. g(x); √(x+1)-2 ; x+-1, 0, 3, 8
g(x) ; √(-1+1)-2=-2
g(x) ; √(0+1)-2=-1
g(x) ; √(3+1)-2=4
g(x) ; √(8+1)-2=1

27. h(x)= |x-3| ; x=0,1,2,3,4,5,6
h(x); |0-3| =3
h(x); |1-3|=4
h(x); |2-3|=5
h(x); |4-3|=7
h(x); |5-3|=8
h(x); |6-3|=9

  • Algebra2 -

    25.
    all squares are positive
    thus f(-3) = (-3)^2-1 = 9-1 = 8
    -3^2 = -9, but (-3)^2 = +9

    when substituting in for x, to avoid mistakes, always enclose the value in ().

    26.
    f(3) = √(3+1)-2 = √4 - 2 = 2-2 = 0

    27.
    |x| = -x if x<0
    |x| = x if x >= 0

    so, |1-3| = |-2| = 2, not 4
    do the addition first, then the ||.
    Treat the || like special parentheses, or treat |x| like a function abs(x), so all the inside stuff is done first

    |1-3| = 2
    |1| + |-3| = 1+3 = 4

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