If a 60N weight free falls onto a hollow ball what amounts of force are produced after 3 seconds of impact, if it lands .3m away of the center?
Dispersal forces travel equally in 3 diameter length vectors.
F1=<9.8><s>[60N]
F2=<9.8><s^2>[120N]
F3=<9.8><s^3>{180N}
Here's where it gets tricky.
Derive the hollow balls diameter from the force:
3F^8(9.8)/Gb[1.333]^W
3F^8=Gb^w(15.66)
Gb^w{180^3x)(120^2y)(60z)+C
[460xyz^6)=d^(1/8)
d=12m
r=6m
ri=5.7m
ContinDisperse=ri^12(F1F2F3)
=900N
900(3)
2700N
Thank you!!!!
To find the amount of force produced after 3 seconds of impact, when a 60N weight free falls onto a hollow ball landing 0.3m away from the center, we need to consider the concept of impulse and momentum.
Impulse is defined as the change in momentum of an object, which can be calculated by multiplying the force acting on the object by the time interval during which the force acts. Mathematically, impulse (J) can be expressed as:
J = F * Δt
where F is the force in Newtons and Δt is the time interval in seconds.
Momentum (p) is the product of an object's mass and velocity and is given by:
p = m * v
where m is the mass of the object and v is its velocity.
In this scenario, the weight of the falling object exerts a force on the hollow ball, causing both objects to create an equal and opposite force on each other due to Newton's third law of motion. This means that the force exerted by the hollow ball on the weight will have the same magnitude but opposite direction.
So, to find the force exerted by the weight on the hollow ball, we calculate the impulse experienced by the weight using its initial momentum and the change in momentum.
First, let's calculate the initial momentum (p_initial) of the weight:
p_initial = m * v_initial
Since the weight is free falling, its initial velocity (v_initial) is zero, so the initial momentum is also zero.
Next, let's calculate the final momentum (p_final) of the weight:
p_final = m * v_final
To find v_final, we need to calculate the final velocity of the weight after 3 seconds of free fall. Since we know the initial velocity is zero and the acceleration due to gravity is approximately 9.8 m/s^2, we can use the equation of motion:
v_final = v_initial + a * Δt
where v_initial = 0 m/s, a = 9.8 m/s^2, and Δt = 3 s.
v_final = 0 + 9.8 * 3 = 29.4 m/s
Now we can calculate the final momentum:
p_final = m * v_final
The mass of the weight is not given in the question, so we cannot calculate the final momentum without this information. However, once we have the final momentum, we can proceed to find the force exerted by the weight on the hollow ball.
Assuming the 60N weight refers to the weight of the hollow ball, we need to find the time interval during which the force acts. Since the weight is free falling and we are considering the impact for 3 seconds, we can assume that the force acts for this entire time interval (Δt = 3s).
Finally, we can calculate the force exerted by the weight on the hollow ball using the impulse-momentum equation:
J = F * Δt
J = p_final - p_initial
F * Δt = m * v_final - m * v_initial
Substituting v_initial = 0 and Δt = 3s, we get:
F * 3 = m * v_final
We don't have the value for the mass of the weight, so we cannot determine the actual amount of force produced without this information.
To find the amount of force produced after 3 seconds of impact, we need to know the mass of the weight.