In a running event, a sprinter does 5.5 105 J of work and her internal energy decreases by 8.8 105 J. Determine the heat transferred between her body and surroundings during this event.
________ J
To determine the heat transferred between the sprinter's body and surroundings, we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:
ΔU = Q - W
Where:
ΔU = change in internal energy
Q = heat added to the system
W = work done by the system
In this case, the sprinter's internal energy decreases, so ΔU is negative:
ΔU = -8.8 * 10^5 J
The sprinter does work, so the work done is positive:
W = 5.5 * 10^5 J
Now, we can rearrange the equation to solve for Q:
Q = ΔU + W
Substituting the given values:
Q = (-8.8 * 10^5 J) + (5.5 * 10^5 J)
Calculating the sum:
Q = -3.3 * 10^5 J
Therefore, the heat transferred between the sprinter's body and the surroundings during the event is -3.3 * 10^5 J (negative because the internal energy decreased).