An athlete whirls a 7.54 kg hammer tied to the end of a 1.5 m chain in a horizontal circle.

The hammer moves at the rate of 1.51 rev/s.
What is the centripetal acceleration of the
hammer? Assume his arm length is included in the length given for the chain.
Answer in units of m/s2

To find the centripetal acceleration of the hammer, we can use the formula:

a = (v^2) / r

where
a is the centripetal acceleration,
v is the tangential velocity of the hammer, and
r is the radius of the circular path.

In this case, the tangential velocity can be determined by multiplying the velocity in revolutions per second (rev/s) by the circumference of the circle:

v = (2πr) * (1.51 rev/s)

Given that the length of the chain is 1.5 m, we can determine the radius of the circular path by subtracting the length of the athlete's arm:

r = 1.5 m - arm length

Now we can substitute these values back into the formula to find the centripetal acceleration:

a = ((2πr) * (1.51 rev/s))^2 / r

Finally, we can simplify and calculate the result.