What is the magnitude of the electric field 0.3 m from a 10-4 C point charge?
To find the magnitude of the electric field generated by a point charge, you can use Coulomb's law. Coulomb's law states that the magnitude of the electric field (E) produced by a point charge is given by the formula:
E = k * (Q / r^2)
Where:
- E is the magnitude of the electric field.
- k is the electrostatic constant, which has a value of approximately 9 x 10^9 Nm^2/C^2.
- Q is the charge of the point charge.
- r is the distance from the point charge.
In this case, the charge of the point charge is Q = 10^-4 C. The distance from the point charge is r = 0.3 m. Plugging these values into Coulomb's law, we can calculate the magnitude of the electric field:
E = (9 x 10^9 Nm^2/C^2) * (10^-4 C) / (0.3 m)^2
Simplifying the equation:
E = (9 x 10^9 N) * (10^-4 C) / (0.09 m^2)
E = (9 x 10^9 N) * (10^-4 C) / (0.09 m^2)
E ≈ 3 x 10^5 N/C
Therefore, the magnitude of the electric field 0.3 m from a 10^-4 C point charge is approximately 3 x 10^5 N/C.