Write the standard form of the equation of the circle with the given center and radius.
1.
center (-2, 0) and r = 3
center at (h,k) and radius r:
(x-h)^2 + (y-k)^2 = r^2
so, plug in your values.
To derive the standard form of the equation of a circle, which is (x - h)^2 + (y - k)^2 = r^2, we need to know the center (h, k) and the radius (r) of the circle.
Given that the center is (-2, 0) and the radius is 3, we can substitute these values into the standard form equation:
(x - h)^2 + (y - k)^2 = r^2
(x - (-2))^2 + (y - 0)^2 = 3^2
(x + 2)^2 + y^2 = 9
Therefore, the standard form of the equation of the circle with center (-2, 0) and radius 3 is (x + 2)^2 + y^2 = 9.