Algebra
posted by Reshanee F .
A rope 116 inches is cut into three pieces.The middlesized piece is 10 inches shorter than twice the shortest piece.The longest piece is 5/3 as long as the shortest piece.What is the length of the shortest piece?

if the pieces are a < b < c,
a+b+c = 116
b = 2a  10
c = 5/3 a
the pieces are 27,44,45
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