Water is the solvent and you can assume the density of water is 1.0g/cc.
a.) What will be the amount of solute in grams if the volume is 500 mL and the concentration of solution is 15% w/w? The molar mass of the solute is H2SO4, 98.0g/mol
b.) What is the molar mass of the solute if the amount of solut is 117.0g, volume of solvent 2.00L, volume of solution 2.00L and concentration of solution is 1.0M? pls help
15% w/w means 15 g H2SO4/100 g solution.
That's 15 g H2SO4/(15 g H2SO4 + 85 g H2O) BUT that doesn't tell us the volume of that 100 grams of solution. I don't know how much solute is in 500 mL because I don't know what 500 mL weighs. You need the density of the SOLUTION. The density of the solvent doesn't help
a.) To find the amount of solute in grams, we can use the equation:
Mass of Solute = Volume of Solution * Concentration of Solution
Given:
Volume of Solution = 500 mL = 0.5 L
Concentration of Solution = 15% w/w = 15 g/100 g = 0.15 g/g
Mass of Solute = 0.5 L * 0.15 g/g = 0.075 g
Therefore, the amount of solute in grams is 0.075 g.
b.) To find the molar mass of the solute, we can rearrange the formula for molarity:
Molarity (M) = Amount of Solute (mol) / Volume of Solution (L)
Given:
Amount of Solute = 117.0 g
Volume of Solution = 2.00 L
Molarity = 1.0 M
Rearranging the formula, we have:
Amount of Solute (mol) = Molarity * Volume of Solution
Amount of Solute (mol) = 1.0 M * 2.00 L = 2.00 mol
Next, we can calculate the molar mass using the equation:
Molar Mass (g/mol) = Mass of Solute (g) / Amount of Solute (mol)
Molar Mass (g/mol) = 117.0 g / 2.00 mol = 58.5 g/mol
Therefore, the molar mass of the solute is 58.5 g/mol.