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N2O5 dissolved in CCl4 decomposes to give N2O4 and O2. The reaction is first order with a half-life of 1234 seconds. How long will it take, in seconds, for the concentration of N2O5 to fall to 1.1% of its initial value?

  • chemistry -

    the fraction left after t seconds is (1/2)^(t/1234)

    so, solve

    (1/2)^(t/1234) = 0.011
    t = 8028.84

    makes sense: .011 is around 1/64, or 6 half-lives

  • chemistry -

    t=8028.84

  • chemistry -

    8028.84

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