How would you prepare the following solution? a)2% NaCL(w/v) b).35M glucose

C)0.12M CaCl2

For b I got glucose 0.35=wt/180=63gm/L, but not sure if I'm doing it right.

2% w/v means 2g NaCl/100 ml solution.

Add 2 g NaCl to a vessel and add enough water to make 100 mL.

b. 63 g glucose/L solution is right IF you do it right. You place 63 g glucose in a 1 L volumetric flask, add some water, swirl until all of the glucose is dissolved, then add water to the mark on the volumetric flask. This makes a total of 1,000 mL (1 L) OF SOLUTION. Note what I did NOT say. You do NOT add 63 g glucose to 1000 mL H2O. WHY? Because doing that gives you more than 1000 mL of solution.
CaCl2 is done the same way as glucose.

a) To prepare a 2% NaCl (w/v) solution, you'll need to dissolve 2g of NaCl (table salt) in 100ml of water. Make sure to measure the weight of NaCl accurately and dissolve it completely in water, or else you might end up with a "salty" solution!

b) For a .35M glucose solution, you seem to be on the right track! Glucose has a molecular weight of 180g/mol, so to prepare 0.35M glucose solution, you'll need to dissolve 63g of glucose in enough water to make a final volume of 1 liter. Just be careful not to get too "sweet" with your calculations!

c) To prepare a 0.12M CaCl2 solution, you'll need to dissolve 4.32g of CaCl2 (calcium chloride) in enough water to make a final volume of 1 liter. But don't Calcium and Chlorine get along swimmingly in water? Make sure to mix everything well to ensure proper dissolution.

a) To prepare a 2% NaCl (w/v) solution:

Step 1: Determine the mass of NaCl needed. To calculate the mass of NaCl required, use the formula:
Mass of NaCl = (Desired concentration in g/L) × (Volume of solution in L)
For a 2% NaCl solution:
Mass of NaCl = (2 g/100 mL) × (1000 mL/1 L) = 20 g/L

Step 2: Weigh out the appropriate amount of NaCl. Measure out 20 grams of NaCl using a digital scale.

Step 3: Add the NaCl to a container. Transfer the measured NaCl into a clean container, e.g., a beaker or a flask.

Step 4: Add water to reach the desired volume. Add water, while stirring or shaking the container, until the solution reaches the desired volume. Ensure that all the NaCl dissolves completely.

b) To prepare a 0.35 M glucose solution:
Step 1: Calculate the molecular weight of glucose. The molecular weight of glucose (C6H12O6) can be calculated by adding the atomic weights of each element:
C = 12.01 g/mol
H = 1.01 g/mol
O = 16.00 g/mol
Molecular weight of glucose = (6 × C) + (12 × H) + (6 × O) = (6 × 12.01) + (12 × 1.01) + (6 × 16.00) = 180.18 g/mol

Step 2: Calculate the mass of glucose needed. To calculate the mass of glucose required, use the formula:
Mass of glucose = (Molarity in mol/L) × (Molecular weight in g/mol)
For a 0.35 M glucose solution:
Mass of glucose = (0.35 mol/L) × (180.18 g/mol) = 63.06 g/L

Step 3: Weigh out the appropriate amount of glucose. Measure out 63.06 grams of glucose using a digital scale.

Step 4: Add the glucose to a container. Transfer the measured glucose into a clean container, e.g., a beaker or a flask.

Step 5: Add water to reach the desired volume. Add water, while stirring or shaking the container, until the solution reaches the desired volume. Ensure that all the glucose dissolves completely.

c) To prepare a 0.12 M CaCl2 solution:
Step 1: Calculate the formula mass of CaCl2. The formula mass of CaCl2 can be calculated by adding the atomic weights of each element:
Ca = 40.08 g/mol
Cl = 35.45 g/mol
Formula mass of CaCl2 = (1 × Ca) + (2 × Cl) = (1 × 40.08) + (2 × 35.45) = 110.98 g/mol

Step 2: Calculate the mass of CaCl2 needed. To calculate the mass of CaCl2 required, use the formula:
Mass of CaCl2 = (Molarity in mol/L) × (Formula mass in g/mol)
For a 0.12 M CaCl2 solution:
Mass of CaCl2 = (0.12 mol/L) × (110.98 g/mol) = 13.318 g/L

Step 3: Weigh out the appropriate amount of CaCl2. Measure out 13.318 grams of CaCl2 using a digital scale.

Step 4: Add the CaCl2 to a container. Transfer the measured CaCl2 into a clean container, e.g., a beaker or a flask.

Step 5: Add water to reach the desired volume. Add water, while stirring or shaking the container, until the solution reaches the desired volume. Ensure that all the CaCl2 dissolves completely.

To prepare the given solutions, you need to calculate the necessary quantities of the solutes and then dissolve them in the appropriate amount of solvent. Let's go through each solution preparation step-by-step:

a) 2% NaCl (w/v):
To prepare a 2% NaCl (w/v) solution, you need to determine how much NaCl to dissolve in a specific volume of water. The "w/v" stands for "weight/volume," which means you will express the concentration as a percentage by weight per volume.

1. Start by converting the percentage to a decimal: 2% = 0.02.
2. Now, calculate the weight of NaCl required by multiplying the desired concentration (0.02) by the final volume of the solution. Let's assume you want to prepare 1 liter (1000 mL) of the solution: 0.02 x 1000 mL = 20 grams of NaCl.

Therefore, to prepare a 2% NaCl (w/v) solution, dissolve 20 grams of NaCl in 1000 mL (1 liter) of water.

b) 0.35 M glucose:
To prepare a 0.35 M glucose solution, you need to calculate the mass of glucose required in a specific volume of solvent. The "M" represents molarity, which is the concentration measured in moles per liter.

1. Determine the molar mass of glucose. Glucose has a molar mass of approximately 180 g/mol.
2. Calculate the amount of glucose required by multiplying the desired molarity (0.35 M) by the molar mass and the final volume of the solution. Assuming you want to prepare 1 liter (1000 mL) of the solution: 0.35 mol/L x 180 g/mol x 1 L = 63 grams of glucose.

Therefore, to prepare a 0.35 M glucose solution, dissolve 63 grams of glucose in 1000 mL (1 liter) of water.

c) 0.12 M CaCl2:
To prepare a 0.12 M CaCl2 solution, you need to determine the mass of CaCl2 required in a specific volume of water.

1. Determine the molar mass of CaCl2. Calcium chloride has a molar mass of approximately 111 g/mol.
2. Calculate the amount of CaCl2 required by multiplying the desired molarity (0.12 M) by the molar mass and the final volume of the solution. Let's assume you want to prepare 500 mL (0.5 liters) of the solution: 0.12 mol/L x 111 g/mol x 0.5 L = 6.66 grams of CaCl2.

Therefore, to prepare a 0.12 M CaCl2 solution, dissolve 6.66 grams of CaCl2 in 500 mL (0.5 liters) of water.