Chemistry
posted by Zach .
I am not sure if I calculated the exact molarity of the potassium permanganate. I multiplied the molarity of the potassium permanganate by the liters of potassium permanganate used in the titration and divided it by the total liters of solution. I don't know if that if how it is done or not.
(0.125M)(0.0378L)/0.0828L= 0.057M KMnO4

If you started with 37.8 mL of 0.125M KMnO4 and diluted it to 82.8 mL total volume, the new M is what you calculated. Without more details, however, I don't know if this will satisfy what you need to be doing.