I am not sure if I calculated the exact molarity of the potassium permanganate. I multiplied the molarity of the potassium permanganate by the liters of potassium permanganate used in the titration and divided it by the total liters of solution. I don't know if that if how it is done or not.
(0.125M)(0.0378L)/0.0828L= 0.057M KMnO4
See your post above.
To calculate the molarity of a solution, you need to divide the number of moles of the solute by the volume of the solution in liters. However, it seems like you may have made a slight error in your calculation.
To calculate the molarity of potassium permanganate (KMnO4), you should follow these steps:
1. Determine the moles of potassium permanganate (KMnO4) used in the titration. To do this, multiply the molarity (0.125M) by the volume used in liters (0.0378L):
Moles KMnO4 = molarity × volume
Moles KMnO4 = 0.125M × 0.0378L = 0.004725 moles
2. Calculate the molarity of potassium permanganate by dividing the moles of KMnO4 by the total volume of the solution in liters (0.0828L):
Molarity = moles KMnO4 / volume
Molarity = 0.004725 moles / 0.0828L = 0.057M
Therefore, the molarity of the potassium permanganate solution is 0.057M, not 0.057M KMnO4. Make sure to include the unit of molarity (M) without specifying the compound.