# Shasha

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What is the exact value of sin(2 theta) if cos (theta)=3/5 and (theta) is in quadrent 4?

12/25
24/25
-12/25
-7/25
-24/25

• Shasha -

sin2θ = 2sinθcosθ

in QIV, if cosθ = 3/5, sinθ = -4/5
so, sin2θ = 2(-4/5)(3/5) = -24/25

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