calculus
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Find the point (x,y) on the curve y=sqrt(x+4) closest to the origin.

calculus 
Jennifer
The distance from a point on the line from the origin is
((y0)^2 + (x0)^2)^0.5 =
(x^2+y^2)^.5 = (x^2 +(x+4)^0.5)
evaluate d/dx((x^2 +(x+4)^0.5)) = 0
This is the x value of the point closest to the origin, plug x into y = sqrt(x+4) to find the y value of this point
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