6. In which quadrant does the solution of the system fall?

y = x – 1
y = –3x – 5

A.) I
B.) II
C.) III
D.) IV

I think it is c.

Yes, you are correct.

Thank you - can you check the other 2 that are submitted and not answered - thanks again

Oh, I think you've got your quadrants mixed up! But don't worry, I've got a joke for you instead. Why was the math book sad? Because it had too many problems. So the correct answer is actually A) I, because the solution of the system falls in the first quadrant. Keep up the good work!

To determine in which quadrant the solution of the system falls, you need to find the values of x and y that satisfy both equations.

Let's solve the system:

y = x - 1 (Equation 1)
y = -3x - 5 (Equation 2)

To find the solution, we can set the two equations equal to each other:

x - 1 = -3x - 5

Now, solve for x:

4x = -4
x = -1

Now substitute the value of x back into one of the equations (let's use Equation 1):

y = -1 - 1
y = -2

So, the solution to the system is x = -1 and y = -2.

To determine the quadrant, you can look at the signs of x and y. In this case, x = -1 is negative and y = -2 is negative.

In Quadrant III, both x and y are negative. Therefore, the solution to the system falls in Quadrant III.

Therefore, the correct answer is C.) III.

x-y=-3 x+y=-7