a. Find the amount of solute based on this information

Volume = 500 ml
Concentration of solution= 15% (w/w)
Solute (molar mass) = H2SO4 is 98.0g/mol
b. Find the molar mass
Amount of solute= 117.0g
Volume of solution= 2.00L
concentration of a solution= 1.0M
volume of solvent = 2.00L
c. find the concentration of the solution (ppm) w/w
solute = 180g/mol(C6H12O6)
amount of solute= 0.0150mg
volume of solvent= 0.125L
d. find the volume of solvent
solute=60.0g/mol(CH3COOH)
amount of solute= 25.0 ml
concentration of solution= 5.00% v/v

500 mL doesn't mean anything without the density. 15% w/w means 15 g H2SO4/100 GRAMS soln. So in 500 GRAMS of soln there is

15 g H2SO4 x 500/100 = ? but in 500 mL who knows.

water is the solvent and it is aasumed its density is 1.0g/cc pls need simple explanation forall of this problems

a. To find the amount of solute based on the given information, you can use the formula:

Amount of Solute = Volume of Solution * Concentration of Solution

In this case, the volume of the solution is given as 500 ml and the concentration of the solution is given as 15% (w/w).

First, convert the volume from ml to L:
Volume of Solution = 500 ml / 1000 = 0.5 L

Now, substitute the values into the formula:
Amount of Solute = 0.5 L * 15% = 0.5 L * 0.15 = 0.075 L

To convert this to grams, you need to know the molar mass of the solute, which is given as 98.0 g/mol (for H2SO4):
Amount of Solute (in grams) = 0.075 L * (98.0 g/mol) = 7.35 g

Therefore, the amount of solute is 7.35 grams.

b. To find the molar mass based on the given information, you can use the formula:

Molar Mass = Amount of Solute / Number of Moles

In this case, the amount of solute is given as 117.0 g and the volume of the solution is given as 2.00 L. The concentration of the solution is given as 1.0 M.

First, convert the volume from L to ml:
Volume of Solution = 2.00 L * 1000 = 2000 ml

Now, substitute the values into the formula:
Number of Moles = Volume of Solution * Concentration of Solution
Number of Moles = 2000 ml * 1.0 mol/L = 2000 mol

Finally, substitute the values into the molar mass formula:
Molar Mass = 117.0 g / 2000 mol = 0.0585 g/mol

Therefore, the molar mass is 0.0585 g/mol.

c. To find the concentration of the solution (ppm) w/w, based on the given information, you can use the formula:

Concentration (ppm) = (Amount of Solute / Volume of Solvent) * 10^6

In this case, the solute is given as 180 g/mol (for C6H12O6), the amount of solute is given as 0.0150 mg, and the volume of solvent is given as 0.125 L.

First, convert the amount of solute from mg to g:
Amount of Solute = 0.0150 mg / 1000 = 0.0000150 g

Now, substitute the values into the formula:
Concentration (ppm) = (0.0000150 g / 0.125 L) * 10^6 = 120 ppm

Therefore, the concentration of the solution (ppm) w/w is 120 ppm.

d. To find the volume of solvent based on the given information, you can use the formula:

Volume of Solvent = (Amount of Solute / Concentration of Solution) * 100

In this case, the solute is given as 60.0 g/mol (for CH3COOH), the amount of solute is given as 25.0 ml, and the concentration of the solution is given as 5.00% v/v.

First, convert the amount of solute from ml to L:
Amount of Solute = 25.0 ml / 1000 = 0.025 L

Now, substitute the values into the formula:
Volume of Solvent = (0.025 L / 0.05) * 100 = 50 L

Therefore, the volume of solvent is 50 L.