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0.2688 of a monoprotic acid neutralizes 16.4mL 0f 0.08133 M KOH. Calculate the molar mass of the acid in units of g/mol

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    0.2688 what? grams?
    HA + KOH ==> KA + H2O
    mols KOH = M x L = ?
    mols HA = mols KOH (look at the coefficients in the balanced equation.)
    mols = grams/molar mass. You know mols and grams, solve for molar mass.

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