# CALCULUS

posted by .

what is the area in square units of the region under the curve of the function f(x)=x+3, on the interval from x=1 to x=3?

10
12
14
16
18 ?

• CALCULUS -

even without calculus, since this is just a trapezoid with bases 4 and 6, height 2.

5*2 = 10

now, using calculus, integrate under the curve, from 1 to 3

integral[1,3] x+3 dx
= x^2/2 + 3x [1,3]
= (9/2 + 9) - (1/2 + 3) = 10

## Similar Questions

1. ### Calculus

These are the two problems from my homework I don't get.. can you help me?
2. ### calculus

find the area of the region under the curve y=f(x)=e^2x over the indicated interval x<2
3. ### Urgent help calculus

If the area in square units of the region under the curve of the function f(x)=5, on the interval from x=a to x=8 is 20 square units what is the value of a?
4. ### Steveeee help plz

What is the area is square units o the region under the curve of the function f(x)=4, on the interveral from x=-1 to x=3
5. ### math

Find the area of the region under the graph of the function f on the interval [4, 10]. f(x)=10x-5 ?
6. ### math

Find the area of the region under the graph of the function f on the interval [-27, -1]. f(x)= 2-3square root x ?
7. ### Calculus

the area of the first quadrant region bounded by the y-axis, the line y=4-x and the graph of y=x-cosx is approximately: a) 4.50 square units, b) 4.54 square units, c) 4.56 square units, d) 4.58 square units, e) 5.00 square units
8. ### calculus

R is the first quadrant region enclosed by the x-axis, the curve y = 2x + b, and the line x = b, where b > 0. Find the value of b so that the area of the region R is 288 square units.
9. ### calculus

R is the first quadrant region enclosed by the x-axis, the curve y = 2x + a, and the line x = a, where a > 0. Find the value of a so that the area of the region R is 18 square units.
10. ### Calculus

Find the area of the region under the curve y=x+2 over the interval [1,4].

More Similar Questions