calculus

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if the distance covered by an object in time is given by s(t)=t^2+5t where s(t) is in metersand t is in seconds, what is the distance covered in the interveral between 1 second and 5 seconds?

  • calculus -

    s(5)-s(1)

  • calculus -

    A 24 meters
    B 30
    C 40
    D 42
    E 44

  • calculus -

    so what would be the answer

  • calculus -

    plug in t=5 and t=1. subtract one from the other. what do you get? you've posted a lot of similar problems. By now you should be getting the hang of them.

  • calculus -

    30 ahh i get it now thanks

  • calculus -

    ummm. what did you do?

    s(5) = 5^2 + 5*5 = 50
    s(1) = 1^1 + 5*1 = 6

    s(5)-s(1) = 44, not 30

  • calculus -

    i did it like this
    5^2=25 + 5^1= 5 = 30
    i guess i did it wrong

  • calculus -

    that's 5t. not 5^t

    5*5 = 25

    you did it wrong in two ways. you tried to do 5^2 + 1^2 but did 5^2 + 5^1 instead.

    You did not include both terms in your evaluations.

    *sigh* review your algebra, if you want to do well in calculus.

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