# calculus

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if the distance covered by an object in time is given by s(t)=t^2+5t where s(t) is in metersand t is in seconds, what is the distance covered in the interveral between 1 second and 5 seconds?

• calculus -

s(5)-s(1)

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A 24 meters
B 30
C 40
D 42
E 44

• calculus -

so what would be the answer

• calculus -

plug in t=5 and t=1. subtract one from the other. what do you get? you've posted a lot of similar problems. By now you should be getting the hang of them.

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30 ahh i get it now thanks

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ummm. what did you do?

s(5) = 5^2 + 5*5 = 50
s(1) = 1^1 + 5*1 = 6

s(5)-s(1) = 44, not 30

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i did it like this
5^2=25 + 5^1= 5 = 30
i guess i did it wrong

• calculus -

that's 5t. not 5^t

5*5 = 25

you did it wrong in two ways. you tried to do 5^2 + 1^2 but did 5^2 + 5^1 instead.

You did not include both terms in your evaluations.

*sigh* review your algebra, if you want to do well in calculus.

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