I'm reclassified but I'm still a 10th grader and the only class I need to take is Algebra1B So here's the problem. I'm 1990, the town of Belgrade, Montana, had a popuof of 3422. For each of the next 8 years, the population increased by 4.9% per year.
a. Write an equation for the population of Belgrade in 1998
b. Find the population of Belgrade in 1998.
pop = 3422(1.049^n , where n is the number of years since 1990
pop = 3422(1.049)^8
= ....
To solve this problem, we need to calculate the population of Belgrade in 1998.
To find the population in any given year, we can use the formula:
P = P0 * (1 + r)^n
Where:
- P is the population in the given year
- P0 is the initial population
- r is the growth rate
- n is the number of years
Let's break down the problem step by step:
a. To write an equation for the population of Belgrade in 1998, we use the given information that the population increased by 4.9% per year. We know the initial population in 1990 is 3422, and we need to calculate the population in 1998, which is 8 years later.
Using the formula, we have:
P = 3422 * (1 + 0.049)^8
b. To find the population of Belgrade in 1998, we substitute the values into the equation:
P = 3422 * (1.049)^8
Now we need to evaluate the expression using a calculator:
P ≈ 4697.49
Therefore, the population of Belgrade in 1998 is approximately 4697.49.