Physics
posted by Tom .
A 2.50 kg wheel has a diameter of 20.0 cm and is rotating at 3600 rpm. A force acts on it causing it to come to a rest in 10.0 seconds. What is the magnitude of the force?

m=2.5 kg. R=D/2=0.1 m,
n₀=3600 rpm=3600/60=60 rev/s
t=10 s. F=?
2πn=2πn₀εt.
Final n=0
2πn₀ = εt.
ε =2πn₀/t.
Newton’s 2 law for rotation:
Iε=M.
If the wheel is disc I=mR²/2,
M=FR.
Then
(mR²/2) •(2πn₀/t)=F•R
F=mRπn₀/t=2.5•0.1•3.14•60/10 = 4.71 N
Respond to this Question
Similar Questions

Physics
The combination of an applied force and a frictional force produces a constant total torque of 38.1 Nm on a wheel rotating about a fixed axis. The applied force acts for 7.00 s, during which time, the angular speed of the wheel increases … 
Physics
Rotating initially at 1800 rpm, a wheel with a diameter of 74.0 cm is brought to rest in 11.0 s. Calculate the magnitude of its angular acceleration in radians/second^2 
physics
A grinding wheel of radius 0.370 m rotating on a frictionless axle is brought to rest by applying a constant friction force tangential to its rim. The constant torque produced by this force is 79.2 N • m. Find the magnitude of the … 
physics
The flywheel of an engine has a moment of inertia of 24 kg*m^2. a) if the radius of the wheel is 0.6m, what force is required to accelerate the wheel from rest to an angular velocity of 300 rpm in 6 seconds? 
physics
The flywheel of an engine has a moment of inertia of 24 kg*m^2. a) if the radius of the wheel is 0.6m, what force is required to accelerate the wheel from rest to an angular velocity of 300 rpm in 6 seconds? 
Physics
A wheel 31.7 cm in diameter accelerates uniformly from 238 rpm to 347 rpm in 5.9 seconds. How far will a point on the rim of the wheel have travelled in this time? 
Physics
A tangential force acts on the rim of a 2.0 kilogram diskshaped wheel (0.50 m radius) and gives the wheel an angular acceleration of 4.8 rad/s^2. Neglect friction and find the magnitude of the force. 
Physics
A tangential force acts on the rim of a 2.0 kilogram diskshaped wheel (0.50 m radius) and gives the wheel an angular acceleration of 4.8 rad/s^2. Neglect friction and find the magnitude of the force 
Physics
The combination of an applied force produces a constant total torque of 39.6 N.m on a wheel rotating about a fixed axis. The applied force acts for 5.3 s. During this time, the angular speed of the wheel increases from 0 to 9.8 rad/s. … 
physics
A car wheel has a moment of inertia of 0.35kg m^2. It takes 50 seconds to come to rest from the initial angular velocity of 45 rpm. Calculate the magnitude of the average friction torque