(2x-1)(x+2)(3x-4)-(4x^2m+7x-2) is simplified to 6x^3+17x^2-25x+10
Is there a question here? Is this Trig?
yes , this is trig. Can you please help me
This is not trig ... it is basic algebra
but anyway
(2x-1)(x+2)(3x-4)-(4x^2m+7x-2) is simplified to 6x^3+17x^2-25x+10
is a false statement, since the first part contains a variable m, which has disappeared in the last part of the statement.
Unless your statement contains a typo and should say
(2x-1)(x+2)(3x-4)-(4x^2x+7x-2) is simplified to 6x^3+17x^2-25x+10
one way to test if your statement is true is to pick any x, say x = 2
we would get
3(4)(2) - (16+14-2)
= 24-28
= -4
the answer part is
6(8) + 17(4)-25(2)+10
= 76
so the statement is false.
To simplify the expression (2x-1)(x+2)(3x-4)-(4x^2+7x-2), we can use the distributive property to remove the parentheses. Here's how you can do this step by step:
1. Start by multiplying the first two binomials: (2x-1)(x+2).
Using the FOIL (First, Outer, Inner, Last) method:
- First: 2x * x = 2x^2
- Outer: 2x * 2 = 4x
- Inner: -1 * x = -x
- Last: -1 * 2 = -2
Combine all the terms: 2x^2 + 4x - x - 2 = 2x^2 + 3x - 2.
2. Now multiply the result from Step 1 by the third binomial (3x-4): (2x^2 + 3x - 2)(3x - 4).
Again, using the FOIL method:
- First: 2x^2 * 3x = 6x^3
- Outer: 2x^2 * -4 = -8x^2
- Inner: 3x * 3x = 9x^2
- Last: 3x * -4 = -12x
Combine all the terms: 6x^3 - 8x^2 + 9x^2 - 12x = 6x^3 + x^2 - 12x.
3. Finally, subtract the last term: (6x^3 + x^2 - 12x) - (4x^2 + 7x - 2).
Remove the parentheses and combine like terms:
6x^3 + x^2 - 12x - 4x^2 - 7x + 2 = 6x^3 - 3x^2 - 19x + 2.
Therefore, the simplified expression is 6x^3 - 3x^2 - 19x + 2.