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A gas is compressed at a constant pressure of 0.800 atm from 6.00 L to 1.00 L. In the process, 380 J of energy leaves the gas by heat.
(a) What is the work done on the gas?

(b) What is the change in its internal energy?

  • Physics -

    W= - p•ΔV = -0.8•(-5)•10⁻³•1.013•10⁵ = =405.2 J
    ΔU =Q+W=-380+405.2=252 J

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