An antitank weapon fires a 3.0 kg rocket which acquires a speed of 50. m/s after traveling 90. cm down a launching tube. Assuming the rocket was accelerated uniformly, what force acted on it?

To find the force that acted on the rocket, we can use the equation for calculating force, which is:

Force = mass * acceleration

First, we need to find the acceleration of the rocket. We can use the equation for uniformly accelerated motion:

v^2 = u^2 + 2as

where:
v = final velocity (50. m/s)
u = initial velocity (0 m/s, since the rocket starts from rest)
a = acceleration (unknown)
s = distance traveled down the launching tube (90. cm or 0.9 m)

Rearranging the equation, we get:

a = (v^2 - u^2) / (2s)

Substituting the given values, we have:

a = (50^2 - 0^2) / (2 * 0.9)

a = 2500 / 1.8

a ≈ 1388.89 m/s^2

Now we can plug the acceleration back into the force equation to find the force that acted on the rocket:

Force = mass * acceleration

Force = 3.0 kg * 1388.89 m/s^2

Force ≈ 4166.67 N

Therefore, the force that acted on the rocket is approximately 4166.67 Newtons.

To find the force acting on the rocket, we can use the equation for average acceleration:

acceleration = (final velocity - initial velocity) / time

First, we need to convert the distance traveled from centimeters to meters:

distance = 90 cm = 90/100 = 0.9 m

Next, we need to find the initial velocity. Since the rocket starts from rest (assuming it starts from rest inside the tube), the initial velocity is 0 m/s.

Given:
- mass of the rocket (m) = 3.0 kg
- final velocity (v) = 50. m/s
- distance (d) = 0.9 m

Now, let's calculate the time it takes to accelerate the rocket using the equation:

distance = (initial velocity * time) + (0.5 * acceleration * time^2)

Rearranging the equation gives us:

0.5 * acceleration * time^2 + initial velocity * time - distance = 0

Since the initial velocity is 0 m/s, the equation simplifies to:

0.5 * acceleration * time^2 - distance = 0

We can solve this equation for time by rearranging it and using the quadratic formula:

time = (-b +/- sqrt(b^2 - 4ac)) / 2a

Substituting the known values:

a = 0.5 * acceleration
b = 0
c = -distance

Simplifying further:

time = sqrt((distance * 4 * a) / (2 * a))

time = sqrt((2 * distance) / acceleration)

Now, we can find the acceleration using the equation for average acceleration:

acceleration = (final velocity - initial velocity) / time

Since the initial velocity is 0 m/s, the equation simplifies to:

acceleration = final velocity / time

We can substitute the known values:

acceleration = 50. m/s / time

Finally, substituting the calculated time and solving the equation will give us the acceleration.

Once we have the acceleration, we can calculate the force using Newton's second law:

force = mass * acceleration

Substituting the known values will give us the force acting on the rocket.

a = (V^2-Vo^2)/2d.

a = (2500-0)/1.8m = 1389 m/s^2.

F = m*a = 3 * 1389 = 4167 N.