Can't figure this math problem out:
Write an algebraic expression for the product of five less than a number and three, less eight, is twenty-eight.
HELP ME PLEASE!!
Product is the answer of a multiplication problem.
3(n - 5) - 8 = 28
3n - 15 - 8 = 28
3n = 28 + 23
3n = 51
n = 17
Sure, I can help you with that!
To write an algebraic expression for this problem, let's break it down and solve step by step.
First, let's define the unknown number. Let's call it "x".
According to the problem, we have five less than a number. This can be written as "x - 5".
Next, we have the phrase "three, less eight". This means we subtract 8 from a given value. So, we can write this as "3 - 8".
Finally, we have the phrase "is twenty-eight", which means our entire expression should equal 28.
Putting it all together, we get the equation:
(x - 5) * (3 - 8) = 28
Now, let's simplify the expression:
(x - 5) * (-5) = 28
To solve for x, we need to isolate it. Here's how we can proceed:
Divide both sides of the equation by -5:
(x - 5) = 28 / (-5)
Simplifying the right side of the equation:
(x - 5) = -5.6
To isolate x, we can add 5 to both sides:
x = -5.6 + 5
Simplifying the right side gives us:
x = -0.6
Therefore, the unknown number is equal to -0.6.
I hope this helps! Let me know if you have any further questions.