How do you prepare 600.0mL of 0.48M Al(NO3)3*9H2O?
Is this correct?
1. Measure out 71g of solution
2. Put approx. 300.0mL of water into container
3. Add the 71g of solution to the water and mix
4. Add more water until 600.0mL of solution is obtained
5. Mix
•Chemistry - DrBob222, Saturday, November 24, 2012 at 8:53pm
I would make some corrections, one major and two or three minor.
1. Measure out 71g of solution
71 g is not right
2. Put approx. 300.0mL of water into container
3. Add the xxg of solution(solute to the water and mix dissolve the solute completely.
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4. Add more water until 600.0mL of solution is obtained
5. Mix
•Chemistry HELP - Anon, Sunday, November 25, 2012 at 2:01am
Isn't the total mass of the Al(NO3)3*9H2O around 247.18 g/mol?
Have I made an error?
Al = about 27
NO3 = about 62 and 3*62 = 186
9H2O = 9*18 = about 162
27 + 186 + 162 = about 375?
To prepare 600.0mL of a 0.48M Al(NO3)3*9H2O solution, we need to calculate the mass of Al(NO3)3*9H2O required.
First, let's calculate the molar mass of Al(NO3)3*9H2O:
Al (26.98 g/mol) + (N (14.01 g/mol) * 3) + (O (16.00 g/mol) * 9) + (H (1.01 g/mol) * 18)
= 26.98 + (14.01 * 3) + (16.00 * 9) + (1.01 * 18)
= 26.98 + 42.03 + 144.00 + 18.18
= 231.19 g/mol
Next, let's calculate the mass of Al(NO3)3*9H2O needed for a 0.48M solution:
Molarity (M) = moles of solute / volume of solution in liters
0.48M = moles of Al(NO3)3*9H2O / 0.600 L
Rearranging the formula:
moles of Al(NO3)3*9H2O = Molarity (M) * volume of solution in liters
moles of Al(NO3)3*9H2O = 0.48M * 0.600 L
moles of Al(NO3)3*9H2O = 0.288 mol
Now, let's calculate the mass of Al(NO3)3*9H2O needed:
mass of Al(NO3)3*9H2O = moles of Al(NO3)3*9H2O * molar mass of Al(NO3)3*9H2O
mass of Al(NO3)3*9H2O = 0.288 mol * 231.19 g/mol
mass of Al(NO3)3*9H2O = 66.54752 g
So, to prepare 600.0mL of a 0.48M Al(NO3)3*9H2O solution, you will need approximately 66.55 grams of Al(NO3)3*9H2O.
Here are the corrected steps:
1. Measure out approximately 66.55g of Al(NO3)3*9H2O (rounded to the nearest gram) using an analytical balance.
2. Put approximately 300.0mL of water into a container.
3. Add the measured mass of Al(NO3)3*9H2O to the water and mix until the solute is completely dissolved.
4. Add more water until the total volume of the solution reaches 600.0mL.
5. Mix the solution thoroughly.
Please note that it's important to measure the mass of the solute accurately and dissolve it completely to ensure the desired concentration of the solution is achieved.