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what is the density of carbon tetrachloride vapor at 0.975 atm and 125 celsius

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    125 C = 398 K
    molar mass of CCl4 = 12 + 4*35.5 = 154 g/mol

    22.4 liters of an ideal gas contains 1 mole at STP, or 0.975*(273/398) = 0.6688 moles at 0.975 atm and 398 K.

    density of CCl4 = 0.6688*154 g/(22.4 l)
    = 4.60 g/l

    You could also calculate moles per volume using
    n/V = P/RT
    and multiply that by the molar mass.

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