How much NaOH (g) would you need to dissolve in water in order to prepare 2.75 L of a NaOH solution in which [OH-]= 0.50 M?
(OH^-) = 0.50M; therefore, NaOH = 0.5M.
How many mols do you need? That's M x L = 0.5M x 2.75L = ?
Then mols = grams/molar mass. You know molar mass and mols, solve for grams.
54.996 or 55.0 g NaOH
Well, to calculate that, we first need to determine the molarity of NaOH in the solution. We know that [OH-] is given as 0.50 M, but since NaOH is a strong base, it will dissociate completely to produce OH- ions. So, the molarity of NaOH would be 0.50 M as well.
Now, we can use the formula:
Molarity (M) = Moles (mol) / Volume (L)
Since we want to prepare 2.75 L of the solution, we have:
0.50 M = Moles (mol) / 2.75 L
Rearranging the equation, we can calculate the moles of NaOH:
Moles (mol) = 0.50 M x 2.75 L
Moles (mol) = 1.375 mol
Now, the molar mass of NaOH is approximately 40 g/mol. So, to find the mass of NaOH required, we multiply the moles by the molar mass:
Mass (g) = 1.375 mol x 40 g/mol
Mass (g) = 55 g
Therefore, you would need to dissolve approximately 55 grams of NaOH in water to prepare 2.75 L of a NaOH solution with a concentration of 0.50 M. But remember, clown bot doesn't recommend eating or using NaOH for anything other than chemistry experiments. Stay safe!
To find the amount of NaOH needed, we can use the formula for molarity:
Molarity (M) = moles of solute / volume of solution in liters
We are given the molarity ([OH-] = 0.50 M) and volume of solution (2.75 L). We need to find the moles of NaOH.
Step 1: Convert volume from liters to moles.
Moles = Molarity x Volume
Moles = 0.50 mol/L x 2.75 L
Step 2: Calculate the mass of NaOH in grams.
Moles = Mass / Molar mass
Mass = Moles x Molar mass
The molar mass of NaOH is:
Na = 22.99 g/mol
O = 16.00 g/mol
H = 1.01 g/mol
Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol
Mass = Moles x Molar mass
Mass = (0.50 mol/L x 2.75 L) x 40.00 g/mol
Calculating:
Mass = 55.0 g
Therefore, you would need to dissolve 55.0 grams of NaOH in water to prepare 2.75 L of a NaOH solution with [OH-] = 0.50 M.