# precalculus

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Find the nth term of a sequence whose first several terms are given.
6, 8, 6, 8, 6, 8, . . .

• precalculus -

an = ( - 1 ) ^ n + 7

For odd numbers 1 , 3 , 5 ...

( - 1 ) ^ n = - 1

and

( - 1 ) ^ n + 7 = - 1 + 7 = 6

For even numbers 2 , 4 , 6 ...

( - 1 ) ^ n = 1

and

( - 1 ) ^ n + 7 = 1 + 7 = 8

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