The revenue in dollars of a company selling its products per month is given as, R(x) = 3000x - 20x^2, while the cost in dollars is given by, C(x) = 600x + 4000. Find and simplify P(x), where P(x) is the profit per month.

lol check your math textbook page 356 question #100.

What textbook? :S

business algebra

... are you from UOIT?

To find the profit per month, we subtract the cost from the revenue.

Given that the revenue is R(x) = 3000x - 20x^2 and the cost is C(x) = 600x + 4000, we can write the profit function P(x) as:

P(x) = R(x) - C(x)

Substituting the given expressions:

P(x) = (3000x - 20x^2) - (600x + 4000)

Simplifying this expression:

P(x) = 3000x - 20x^2 - 600x - 4000

P(x) = -20x^2 + 2400x - 4000

Therefore, the profit function P(x) is -20x^2 + 2400x - 4000.