how to prepare 300ml of .250M HCl from a 1.00 M HCl stock solution
Use c1v1 = c2v2
c = concn
v = volume
don't
To prepare 300 mL of a 0.250 M HCl solution from a 1.00 M HCl stock solution, you can use the dilution formula:
C1V1 = C2V2
Where:
C1 = initial concentration (1.00 M)
V1 = initial volume (unknown)
C2 = final concentration (0.250 M)
V2 = final volume (300 mL)
Let's solve for V1:
1.00 M x V1 = 0.250 M x 300 mL
V1 = (0.250 M x 300 mL) / 1.00 M
V1 = 75 mL
So, you will need 75 mL of the 1.00 M HCl stock solution and then add enough distilled water to make the final volume 300 mL. Here's how you can prepare the solution:
1. Measure 75 mL of the 1.00 M HCl stock solution using a graduated cylinder or pipette.
2. Add the 75 mL of stock solution to a clean and dry 300 mL volumetric flask.
3. Fill the volumetric flask with distilled water until it reaches the 300 mL mark on the neck of the flask.
4. Mix the solution thoroughly by swirling the contents in the volumetric flask.
5. Your 0.250 M HCl solution is now prepared and ready for use.