precalculus

posted by .

x= 3^log_3_^8 ? The log being in the exponent is throwing me off.

  • precalculus -

    I don't get the question-what are the dashes for?

  • precalculus -

    No reason, basically the equation is supposed to read 3^log base 3^8?

  • precalculus -

    recall the definition of logarithm:

    b^log_b(n) = n

    3^log_3(8) = 8

    log_3(8) is the exponent of 3 which produces 8

    log_10(100) = 2 because 10^2 = 100

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. domain

    How do you find the domain of log(x^2-4)?
  2. TRig WIth LoGs help1!!

    i have problem i can't solve and the book is no help.. anyone got osme hints or somehting i could start off doing?
  3. Math

    The problem 8^x = 16^x+2 the choices a)8 and b)-8. Help please! Given that information I want to say the answer is -8 ?
  4. Precalculus

    PLEASE HELP ME WITH THESE QUESTION AS MUCH AS POSSIBLE!! Evaluate without a calculator. Give exact answers: a) log(log(10)) = ?
  5. math

    Logarithm!!! Select all of the following that are true statements: (a) log(2x) = log(2) + log(x) (b) log(3x) = 3 log(x) (c) log(12y) = 2 log(2) + log(3y) (d) log(5y) = log(20y) – log(4) (e) log(x) = log(5x) – log(5) (f) ln(25) …
  6. PreCalculus

    Hi i don't know how to do this problem solve for n^3 given that log(40 SQRT(3))/log(4n) = log(45)/log(3n) Thanks i'm copletely lost and don't know how to solve
  7. Precalculus

    Evaluate log(Base4) ^3sqrt64 (The ^3 is an exponent infront of sqrt 64) I keep getting wrong answer :|
  8. Math

    Are all statements that are true. (a) log(A)/log(B)=In(A)/In(B) (b) In log[b](N), the exponent is N. (c)If 2log[3](81)=8, then log[3](6.561)=8 (d)log[b](N) negative when N is negative. (e)In(x/2)=In(x)/2
  9. Math

    Are all statements that are true. (a) log(A)/log(B)=In(A)/In(B) (b) In log[b](N), the exponent is N. (c)If 2log[3](81)=8, then log[3](6.561)=8 (d)log[b](N) negative when N is negative. (e)In(x/2)=In(x)/2
  10. Advanced Functions/ Precalculus Log

    1. Evaluate 4^(log base4 64) + 10^(log100) 2. Write 1+log(base2)x^3 as a single logarithm 3. Write log(base b)√(x^3 y z^6) 4. Solve log(base 2)x-log(base 2)6=log(base 2)5+2log(base 2)3 5. Solve 3^(2x) = 9(81^x) 6. Solve 3^(2x)=7^(3x-1). …

More Similar Questions