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find all the values of X between 0 and 2π such that cos(3x-π/2) = -√3/2

  • math -

    cos(3x- ƒÎ/2) = sin(3x)
    (Check your trig identities)

    3x = sin^-1(-ã3/2)
    = 4 pi/3, 5 pi/3, 10 pi/3, 11 pi/3 etc

    x = 4 pi/9 etc

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