if the equilibrium mixture contains 0.100M NO2, and N2O4 is 4.6 x 10-3 what is the concentration?
4.6E-4 what?
What is the concn of what?
To find the concentration of N2O4 in the equilibrium mixture, we need to use the equilibrium expression and the given concentrations of NO2 and N2O4.
The balanced chemical equation for the reaction between NO2 and N2O4 is:
2NO2 ⇌ N2O4
The equilibrium expression for this reaction is:
Kc = [N2O4] / ([NO2]^2)
Given:
[NO2] = 0.100 M
[N2O4] = 4.6 x 10^-3 M
Substituting the given values into the equilibrium expression, we have:
Kc = (4.6 x 10^-3) / (0.100^2)
Now we can calculate the value of Kc:
Kc = 4.6 x 10^-3 / 0.010
Kc ≈ 0.46
Therefore, the concentration of N2O4 in the equilibrium mixture is approximately 0.46 M.