A puncture in the tubing of a refrigerator can cause severe frosbite as chloroethane C2H5Cl, vaporizes. Use this thermochemical equation to calculate the heat absprbed when 23.6g of chloroethane vaporizes at its boiling point (9.66kj)
C2H5Cl(liquid) + 26.4kj arrow C2H5Cl(gas).
You took care of one of my questions. The other is what's the difference between the 9.66 kJ and the 26.4 kJ.
The equation says that 26.4 kJ heat is absorbed when converting liquid to gas and I guess that's for 1 mol. If you had no other information (like the 9.66) there I would answer
26.4 kJ x (23.6 g/molar mass C2H5Cl) = ?
But I don't know what the 9.66 is doing there.
I don't know either. I will have to ask my teacher about it. Thanks for helping :)
To calculate the heat absorbed when 23.6g of chloroethane (C2H5Cl) vaporizes, we need to use the given thermochemical equation:
C2H5Cl(liquid) + 26.4 kJ ⇌ C2H5Cl(gas)
The equation shows that 26.4 kJ of heat is absorbed when 1 mole of chloroethane vaporizes. To start, we need to determine how many moles of chloroethane are present in 23.6g.
1. Calculate the molar mass of chloroethane (C2H5Cl):
Molar mass of C: 12.01 g/mol
Molar mass of H: 1.01 g/mol
Molar mass of Cl: 35.45 g/mol
Total molar mass: (2 * 12.01) + (6 * 1.01) + 35.45 = 64.51 g/mol
2. Calculate the number of moles:
Moles = Mass / Molar mass
Moles = 23.6g / 64.51 g/mol
3. Use the balanced thermochemical equation to determine the heat absorbed per mole of chloroethane:
Heat absorbed per mole = 26.4 kJ / 1 mole
4. Calculate the heat absorbed for 23.6g of chloroethane:
Heat absorbed = number of moles * heat absorbed per mole
Plug in the numbers:
Molar mass = 64.51 g/mol
Moles = 23.6g / 64.51 g/mol = 0.3652 mol
Heat absorbed per mole = 26.4 kJ / 1 mole
Heat absorbed = 0.3652 mol * 26.4 kJ/mol
Now, calculate the final value:
Heat absorbed = 0.3652 mol * 26.4 kJ/mol = 9.62 kJ
Therefore, when 23.6g of chloroethane vaporizes at its boiling point, the heat absorbed is 9.62 kJ.